Calculate the maximum age of the Universe.  Use a minimum value of Hubble's constant.

Solution:

V = Hd = d/t      where V is the Velocity, H is the Hubble's constant, d is the distance and t is the time.

Hence H = 1/t or t = 1/H.

Using a minimum value of Hubble's constant (50 km/s/1000000 pc) where km = kilometers, s = seconds, and p = parsec.

1 pc =  3.086 x 10¹³ km.  Hence 1000000 pc = 3.086 x 10¹⁹ km.

So the age of the Universe in seconds is 3.086 x 10¹⁹ / 50 which equals 6.17 x 10¹⁷ seconds or 19.5 billion years.
 
 
 
 

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